\(T = 2\pi\sqrt{\frac{2.5}{9.8}}\)
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- \(= 5000 \times 0.9604 \approx 4802 \, \text{hectares}\)
- #### 4802
- 問題:** 物理学の実験で、学生が全長2.5メートルの振り子を作ります。重力加速度が\(9.8 \, \text{m/s}^2\)の場合、振り子の周期を計算してください。公式 \(T = 2\pi\sqrt{\frac{L}{g}}\) を使用します。
- \(\sqrt{\frac{2.5}{9.8}} \approx \sqrt{0.2551} \approx 0.505\)
- \(T \approx 2\pi \times 0.505 \approx 3.17 \, \text{seconds}\)
- #### 3.17
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