P(\text{at least 2 of each color}) = \frac{0}{3003} = 0

February 22, 2026

$P(\text{at least 2 of each color}) = \frac{0}{3003} = 0$

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We are looking for selections with **at least 2 red, 2 green, and 2 blue** buses. But since we're only selecting 5 buses, it's **impossible** to have at least 2 of each color (since $2+2+2 = 6 > 5$).
Thus, the number of favorable outcomes is:
### Step 3: Compute the probability
Question: A historian of science is organizing a panel with 3 experts selected from a list of 6 historians, 5 scientists, and 4 physicians. What is the probability that the panel includes at least one expert from each profession?
We are selecting 3 experts from a total of $ 6 + 5 + 4 = 15 $ professionals.
We want the probability that the 3 selected include **at least one historian, one scientist, and one physician**.

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