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$ N = 12 $ (total de bolas),
$ K = 5 $ (bolas rojas),
$ n = 4 $ (seleccionadas),
$ k = 2 $ (bolas rojas seleccionadas).
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\[ f(3) = 3(3)^2 - 2(3) + 1 = 3 \times 9 - 6 + 1 = 27 - 6 + 1 = 22. \]
\[ g(f(3)) = g(22) = 22 - 4 = 18. \]