\( 19.6s = 1600 \)

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• \( v^2 = u^2 + 2as \), où \(v = 0\), \(u = 40\), \(a = -9.8\), et \(s\) est la hauteur maximale.
• \( 0 = 40^2 + 2(-9.8)s \)
• \( 0 = 1600 - 19.6s \)
• \( s = \frac{1600}{19.6} \approx 81.63 \, \text{m} \)
• #### 81.63
• Si \(x^2 - 5x + 6 = 0\), quelles sont les valeurs de \(x\) ?

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