\[ 10b = 15 \]

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• \[ 3(2b - 1) + 4b = 12 \]
• \[ 6b - 3 + 4b = 12 \]
• \[ 10b - 3 = 12 \]
• \[ b = \frac{3}{2} \]
• Now substitute \( b = \frac{3}{2} \) back into \( a = 2b - 1 \):
• \[ a = 2\left(\frac{3}{2}\right) - 1 \]

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