- 15 + n = 120 \implies n = 120
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- \( P(1) = k(1)^2 + m(1) + n = 120 \implies k + m + n = 120 \)
- \( P(2) = k(2)^2 + m(2) + n = 150 \implies 4k + 2m + n = 150 \)
- \( P(3) = k(3)^2 + m(3) + n = 210 \implies 9k + 3m + n = 210 \)
- \( p(1)^2 + q(1) + r = 10 \implies p + q + r = 10 \)
- \( p(2)^2 + q(2) + r = 18 \implies 4p + 2q + r = 18 \)
- \( p(3)^2 + q(3) + r = 30 \implies 9p + 3q + r = 30 \)
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